Suppose you want to validate so that a phrase starts with "string" and ends with "bee", but does not contain "like". Word-constituent characters are letters, digits, and the underscore. You could use this regular expression (which uses a negative lookahead): (?!.*like)^sting. If it contains … The word at point is first character sorted so that dollars becomes adllors in a temporary buffer. I've been trying to get a specific regex working but I can't get it to do what I need. If a line can meet any out of series of requirements, simply use alternation in the regular expression. Check out my new REGEX COOKBOOK about the most commonly used (and most wanted) regex . Similarly, it must be either at the end of the line or followed by a non-word constituent character. Hi fristi, I want it to match any whole sentence that begins with, ends with or contains a string. If you want to match a word A in a string and not to match a word B. * $ matches a complete line of text that contains any of the words “one”, “two” or “three”. In this case the string is virus. Ask Question Asked 10 years, 7 months ago. Dear colleagues, I am trying to write regex, that can match one word with uppercase letters or multiple words, separated by whitespace. Active 1 year ago. java word can lie anywhere in the data string. ^[a-zA-Z0- 9_]*$ A string that contains multiple spaces in between words, “Hello World”. Regular expression for a string containing one word but not another. Regular expressions (regex or … We can grep an exact match by putting a regex match of beginning(^) and ending($) char. I have a two pets - … For those interested in the details, the technique employed is to convert the regular expression that matches the word into a finite automaton, then invert the automaton by changing every acceptance state to non-acceptance and vice versa, and then converting the resulting FA back to a regular expression. 3. Method 1: grep for first and last character. Java regex to match word with nonboundaries – contain word example. A compatible regular expression with basic syntax only would be: [0-8]\d\d|\d[0-8]\d|\d\d[0-8] This does also match any three digits sequence that is not 999. Suppose, you want to match “java” such that it should be able to match words like “javap” or “myjava” or “myjavaprogram” i.e. So, 'input damian whatever' is a match, while 'input damian type whatever' is not. Greetings, I have a problem with finding a regex pattern that should match any text containing a group of letters, and in the same time it does not contain another group of letters. * \b (one | two | three) \b. Basically, I want it to look for ROCKET. … ^. Regex match string containing word. The regex should match ROCKET in upper or lower cases, and with or without punctuation, but not when part of another word. The first backreference will contain the word the line actually contains. Here's one way to implement some equivalent to the "AND"ing of regexp needed for this specific application. Example 1. I want to create an expression that will identify any URL that contains the string selector=size but does NOT contain details.cfm. For example: If you have a text: 1. Iterating a file line by line, I need to extract the lines containing the word 'input', AND not containing the word 'type'. 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